Alkanes of Pharmaceutical Importance – PST05106 Pharmaceutical Organic Chemistry
NTA Level 5 • Semester 1 • PST05106 Alkanes of Pharmaceutical Importance Pharmaceutical Organic Chemistry • Source Session/Topic 8 Full source-text version: all educational wording from the extracted learning source is retained; only presenter/tutor metadata and web-layout noise are removed, while formatting is improved for readability. Session 8: Alkanes of Pharmaceutical Importance. Total Session Time: 120 minutes Prerequisites • None Learning Tasks By the end of this session students are expected to be able to: • Define alkanes • List alkanes and their isomers • Explain nomenclature of alkanes • Draw chemical structure of alkanes • List chemical properties of alkanes • Explain chemical reactions of alkanes Resources Needed: • Flip charts, marker pens, and masking tape. • Black/white board and chalk/whiteboard markers. SESSION OVERVIEW |Step |Time |Activity/ |Content | | | |Method | | |1 |05 minutes |Presentation |Introduction, Learning Tasks | |2 |10 minutes |Brainstorming |Definition of Alkanes | | | |Presentation | | |3 |15 minutes |Buzzing |Alkanes and their Isomers | | | |Presentation | | |4 |15 minutes |Presentation |Nomenclature of Alkanes | |5 |15 minutes |Presentation |Chemical Structure of Alkanes | |6 |10 minutes |Brainstorming |Chemical Properties of Alkanes | | | |Presentation | | |7 |30 minutes |Group |Chemical Reactions and Uses of | | | |discussion |Alkanes | | | |Presentation | | |8 |10 minutes |Presentation |Key Points | |9 |10 minutes |Presentation |Evaluation | SESSION CONTENTS STEP 1: Presentation of Session Title and Learning Tasks (5 minutes) READ or ASK students to read the learning tasks and clarify ASK students if they have any questions before continuing. STEP 2: Definition of Alkanes (10 minutes). |Activity: Brainstorming (5 minutes) | | | |Ask students to brainstorm on the following question: | | | |What is Alkane? | | | |ALLOW few students to respond. | | | |WRITE their responses on the flip chart/ board. | | | |CLARIFY and SUMMARISE by using the content below; | • Alkane or Paraffin is an acyclic saturated hydrocarbon composed of only carbons and hydrogen atoms and contain carbon-carbon single bonds. • Compounds that contain only carbon and hydrogen are called hydrocarbons. Homologous series (homo is Greek for “the same as”) is a family of compounds in which each member differs from the next by one methylene group (CH2). • The general molecular formula for an alkane is CnH2n+2 where n is an integer. • Members (CnH2n+2) o Methane CH4 o Ethane C2H6 o Propane C3H8 o Butane C4H10 o Pentane C5H12 o Hexane C6H14 o Heptane C7H16 o Octane C8H18 o Nonane C9H20 o Decane C10H22 o Undecane C11H24 etc • So, if an alkane has one carbon atom, it must have four hydrogen atoms; if it has two carbon atoms, it must have six hydrogen. NOTE; Only one possible structure for an alkane with molecular formula CH4 (methane) and molecular formula C2H6 (ethane) • There are two possible structures for an alkane straight-chain and a branched structure. • Both of these structures fulfill the requirement that each carbon forms four bonds and each hydrogen forms only one bond. STEP 3: Alkanes and their Isomers (15 minutes). |Activity: Buzzing (5minutes) | | | |ASK students to pair up and buzz on the following question for 5 | |minutes. | | | |What is an isomer? | |What is isomerism? | |ALLOW pairs to respond on the question. | | | |WRITE their response on the flip chart/board. | | | |CLARIFY and SUMMARIZE by using the content below | • Isomers Refers to different compounds having the same molecular formula but different structural formula (have different arrangements of atoms in space). • In n-alkanes, no carbon is bonded to more than two other carbons, give rise to a linear chain. • When carbon is bonded to more than two other carbons, a branched is formed. Example.1; C6H14 has 5 isomers as follows: o Hexane o 2-Methylpentane o 3-Methylpentane o 2,2-Dimethylbutane o 2,3-Dimethylbutane Example.2; C7H16 has 9 isomers as follows: o Heptane o 2-Methylhexane o 3-Methylhexane o 2,2-Dimethylpentane o 2,3-Dimethylpentane o 2,4-Dimethylpentane o 3,3-Dimethylpentane o 3-Ethylpentane o 2,2,3-Trimethylbutane Example 3; C5H12 has 3 isomers which are: o Pentane o 2-Methylbutane o 2,2-Dimethylpropane Example 4; C4H10 has 2 isomers which are; o Butane o 2-Methylpropane STEP 4: Nomenclature of Alkanes (15 Minutes). • Rule1. Determine the longest continuous carbon chain. o This chain is called the parent hydrocarbon. • Rule 2. In isomeric compounds (II and III), indicate by a number the Carbon to which the alkyl group is attached. • Rule 3. In numbering the parent chain, start at whichever end resulting in the use of the lowest numbers; thus, II is called 2–‐ methylpentane rather than 4–‐ methylpentane. • Rule 4. If the same alkyl group occurs more than once as a side chain, indicate this by the prefix di-, tri-, tetra- etc., to show how many of these alkyl groups are there and indicate by various numbers the position of each group, as in 2,2,4‐trimethyl-pentane. [pic] • Rule 5 If there are several different alkyl groups attached to the parent chain, name them in alphabetical order, as in 3,3‐diethyl-5- isopropyl-4-methyloctane [pic] STEP 5: Chemical Structure of Alkanes (15 minutes). • All acyclic alkanes (unbranded and branched) have the characteristic molecular formula CnH2n+2, where n is the number of carbon atoms in the chain. • Gives the molecular formulas and Lewis structure for the unbranched and n-alkanes (n stands for normal) [pic] STEP 6: Chemical Properties of Alkanes (10 minutes). |Activity: Brainstorming (5minutes) | | | |ASK students to pair up and brainstorm on the following question for 5 | |minutes. | | | |What are the chemical properties of Alkanes? | | | |ALLOW pairs to respond on the question | | | |WRITE their response on the flip chart/board | | | |CLARIFY and SUMMARIZE by using the content in the table 1 below | • Combustion o Complete combustion (Under sufficient amount of oxygen (Air)) any hydrocarbon produces carbon